EMF and internal resistance (PAG 5)
Determine EMF and internal resistance from a terminal pd vs current graph.
Apparatus
- Cell or battery
- Variable resistor (rheostat)
- Ammeter (in series) and voltmeter (across terminals)
- Switch and leads
Safety
- Do not short-circuit the cell.
- Open switch between readings.
Method
- Connect circuit with ammeter in series and voltmeter across cell terminals.
- Adjust rheostat to give eight different current values. Record V and I.
- Open switch between readings to prevent discharge.
- Plot V vs I: y-intercept $= \varepsilon$; gradient $= -r$.
Key Variables
Independent
Current I
Dependent
Terminal pd V
Controlled
Same cell; Temperature
Analysis and Results
- $V = \varepsilon - Ir$. Y-intercept $= \varepsilon$; gradient $= -r$.
- X-intercept gives short-circuit current $I_{sc} = \varepsilon/r$.
Common Errors
- Voltmeter across external resistor not cell terminals.
- Not opening switch between readings.
- Plotting V vs R rather than V vs I.
Exam-style questions on this practical. Click Show mark scheme to reveal the answer after attempting each question.
Q14 marks
A cell has EMF 1.50 V and internal resistance 0.60 $\Omega$. It drives a current through an external $4.4$ $\Omega$ resistor. Calculate (a) the current and (b) the power dissipated in the internal resistance.
Q22 marks
The student measures a terminal pd of 1.47 V when the circuit is open (no current). Explain whether this equals the EMF.